LEO / GEO comparison

Using the formulas for the speed and period of a circular orbit (v = sqrt(GM/r) and T = 2pisqrt(r^3/(GM))), explain why a low Earth orbit satellite (LEO, r ~ 6,800 km) moves faster but takes much less time to complete a full revolution than a geostationary satellite (GEO, r ~ 42,164 km). Support your reasoning with an approximate calculation of both speeds and both periods, taking G*M(Earth) ~ 3.986 x 10^14 (SI units).