Motion of a proton in a uniform field
Open answerA proton (q = +1.6x10^-19 C, m = 1.67x10^-27 kg) enters, with no initial speed, a uniform electric field E = 5x10^4 V/m, oriented in the direction of its motion. Qualitatively describe the type of motion of the proton, then calculate the value of its acceleration.

