The concept of a primitive
Primitives of common functions
Table of common antiderivatives
| Function f | Antiderivative F | Interval |
|---|---|---|
| f(x) = a (constant) | F(x) = a*x | R |
| f(x) = x^n (n an integer, n ≥ 1) | F(x) = x^(n+1)/(n+1) | R |
| f(x) = 1/x² | F(x) = -1/x | ]0;+∞[ or ]-∞;0[ |
| f(x) = 1/√x | F(x) = 2*√x | ]0;+∞[ |
| f(x) = 1/x | F(x) = ln(x) | ]0;+∞[ |
| f(x) = e^x | F(x) = e^x | R |
| f(x) = cos(x) | F(x) = sin(x) | R |
| f(x) = sin(x) | F(x) = -cos(x) | R |
Linearity
If F is an antiderivative of f and G is an antiderivative of g, then:
- F + G is an antiderivative of f + g
- kF is an antiderivative of kf (where k is real)
Example: an antiderivative of 5x^2 + 3 is 5*(x^3/3) + 3x = (5/3)x^3 + 3x.
Detailed example
Find an antiderivative of f(x) = 4x³ - 2x + 7 on ℝ. We deal with each term: the antiderivative of 4x³ is x⁴, the antiderivative of -2x is -x², and the antiderivative of 7 is 7x. Therefore, F(x) = x⁴ - x² + 7x + C.
Common pitfall
Do not confuse the antiderivative of x^n with its derivative: we ADD 1 to the exponent and DIVIDE by this new exponent (the inverse of the differentiation rule, which multiplies and subtracts 1). Always check by differentiating F to find f.

