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Modulus, argument and exponential form
Counting the roots
MCQ
How many solutions does the equation z⁵ = 1 have in C, and how are they placed?
Possible answers
Only one,
z
=
1
z = 1
z
=
1
Two,
z
=
1
z = 1
z
=
1
and
z
=
−
1
z = -1
z
=
−
1
Five, evenly spaced on the unit circle
Infinitely many, because the argument is defined modulo
2
π
2\pi
2
π
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