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Invertible matrices and solving systems
Invertible or not?
MCQ
Let A = [[2, 3], [4, 6]]. What can be asserted?
Possible answers
A
A
A
is invertible; its inverse is computed with the
2
×
2
2 \times 2
2
×
2
formula
A
A
A
is invertible and its rank is
2
2
2
A
A
A
is not invertible, because its determinant is zero
A
A
A
is not invertible, so
A
X
=
B
AX = B
A
X
=
B
never has a solution
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