Pulsars
0 %
Log inSign up

Transitions and Photons

The Hydrogen Atom and Its Series

The formula for hydrogen's levels

For the hydrogen atom, the simplest one (a proton, an electron), the energy levels follow a remarkably simple formula, where n is an integer called the principal quantum number:

   E_n = -13,6 / n^2   (en eV),   avec n = 1, 2, 3, ...

Let's compute the first few:

   n=1 :  E = -13,6 / 1   = -13,60 eV   (fondamental)
   n=2 :  E = -13,6 / 4   =  -3,40 eV
   n=3 :  E = -13,6 / 9   =  -1,51 eV
   n=4 :  E = -13,6 / 16  =  -0,85 eV
   n=∞ :  E = 0                          (ionise)

We recover exactly the diagram seen in the previous chapter, and we see why the levels crowd together toward the top: as 1/n^2, they accumulate near E = 0.

The line series

All the transitions that end at the same low level form a series of lines. Each series falls in a different range of wavelengths:

   E=0  ------------------------------  (ionisation)
        |   |   |
   n=4  ---+---+---+----------
        |  |   |   |
   n=3  -+-+---+---+-----  ---.        transitions VERS n=3
        | |    |   |          |----> serie de PASCHEN (infrarouge)
   n=2  -+-+---+----  ---.
        | |    |        |----------->  serie de BALMER (visible !)
        | |    |        |
   n=1  -+-+----  ---.
                    |------------------> serie de LYMAN (ultraviolet)
  • Lyman series: all the transitions toward n=1. Large energy gaps -> very energetic photons -> ultraviolet (invisible).
  • Balmer series: transitions toward n=2. Medium gaps -> visible light. It is the only series visible to the eye: these are the famous red, blue, and violet lines of hydrogen.
  • Paschen series: transitions toward n=3. Small gaps -> infrared (invisible).

A complete calculation: the red line of hydrogen

Let's compute the wavelength of the photon emitted during the transition n=3 -> n=2 (the red Balmer line).

   ΔE = E3 - E2 = (-1,51) - (-3,40) = 1,89 eV

Converting to joules: ΔE = 1,89 × 1,6 × 10^-19 ≈ 3,0 × 10^-19 J. Then, from ΔE = hc/λ, we get:

   λ = h c / ΔE
     = (6,6 × 10^-34 × 3,0 × 10^8) / (3,0 × 10^-19)
     ≈ 6,6 × 10^-7 m
     = 660 nm

660 nm is red — exactly the color of hydrogen's most famous line. The level diagram therefore predicts, within calculation accuracy, the colors observed in the spectrum.

In summary

Hydrogen's levels are E_n = -13,6/n^2 eV, which explains their crowding toward the top. Transitions toward the same low level form series: Lyman (toward n=1, UV), Balmer (toward n=2, visible), Paschen (toward n=3, IR). Computing ΔE and then λ = hc/ΔE reproduces precisely the colors of the observed lines — theory and experiment meet.